ABB ACS880-01 - Calculating the Short-Circuit Current of the Installation

Supply transformer minimum apparent power S
N
(kVA)Cable typeACS880-
01-…
Maximum cable length with
aR fuses
Maximum cable length with
gG fuses
Alumin-
um
Copper
200 m100 m10 m100 m50 m10 mmm
2
mm
2
131313383737-3×6023A-7
131313383737-3×10027A-7
1414144443433×253×10035A-7
2423236867663×253×16042A-7
2423236867663×253×16049A-7
4140409088873×353×25061A-7
6159581491441413×503×35084A-7
1451381341461431413×703×50098A-7
1451381341921871833×953×70119A-7
2051921842862752673×1203×95142A-7
2051921845154764523×1853×120174A-7
2952772666546085842×(3×95)3×185210A-7
2892752666406055842×(3×120)3×240271A-7
￭ Calculating the short-circuit current of the installation
Check that the short-circuit current of the installation is at least the value given in the
fuse table.
The short-circuit current of the installation can be calculated as follows:
I
k2-ph
=
2 ·
R
c
2
+ (Z
k
+ X
c
)
2
U
where
Short-circuit current in symmetrical two-phase short-circuit
I
k2-ph
Network line-to-line voltage (V)
U
Cable resistance (ohm)
R
c
Z
k =
z
k
· U
N
2
/S
N
= transformer impedance (ohm)Z
k
Transformer impedance (%)
z
k
Transformer rated voltage (V)
U
N
Nominal apparent power of the transformer (kVA)
S
N
Cable reactance (ohm)
X
c
Technical data 209