frequency of V
ts
= 50 Hz
I I
I
I
A
s
CTs
CTp
50 50
10459
1
9000
1 162= × = × = .
EQUATION14059 V1 EN-US (Equation 69)
∠I
50s
= 0º
frequency of I
50s
= 50 Hz
It I
I
I
A
fs
CTs
CTp
tf= × = × =10459
1
9000
1 162.
EQUATION14062 V1 EN-US (Equation 70)
∠I
tfs
= 0º
frequency of I
tf
= 50 Hz
• Check that the service values (VOLTAGE, CURRENT, R(%), X(%)) are
according to the injected quantities and that ROTORANG is close to 0 rad. For
this particular injection the service values are:
• VOLTAGE= 6.49 kV
• CURRENT= 20918 A
• R= –0.32%
• X=–32.57%
• ROTORANG= 0.08 rad
Note that these values identify a point outside the lens characteristic, even if it is
close to the point SE. Neither START nor TRIP is issued.
Execution of the dynamic test
GUID-31EF4F76-8FC8-4952-896C-B3A8A5FD635A v1
The test may be performed by using two states of a sequence tool that is a basic feature
of test sets.
• State 1: pre-test condition.
Steady voltage and current are applied in order to get a steady high impedance,
that is, a point in the plane R-X which is far away from the lens characteristic.
Define the following three-phase symmetrical quantities (the phase angle is related
to phase L1):
V V
V
V
V
ts t RvsZ
VT s
VT p
= × × = × × =1 1 1 1 5899
0 1
13 8
47 02. .
.
.
.
,
,
,
EQUATION14069 V1 EN-US (Equation 71)
29.60
arctan 180 arctan 180 90.56
0.29
ts
ReverseX
V
ReverseR
Ð = - ° = - ° = - °
æ ö æ ö
ç ÷ ç ÷
è ø è ø
EQUATION14068 V1 EN-US (Equation 72)
1MRK 502 073-UUS A Section 13
Testing functionality by secondary injection
Generator protection REG670 2.2 ANSI and Injection equipment REX060, REX061, REX062 177
Commissioning manual
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