I
tfs
=0 A
• State 2: main test step.
Define the following three-phase symmetrical quantities (the phase angle is related to
phase L1):
V V
V
V
V
ts t FwdZ
VT s
VT p
= × × = × × =1 1 1 1 11931
0 1
13 8
95 1. .
.
.
.
,
,
,
EQUATION14057 V1 EN (Equation 23)
∠ =
=
=V
ForwardX
ForwardR
ts
arctan arctan
.
.
59 33
8 19
82..14°
EQUATION14058 V1 EN (Equation 24)
frequency of V
ts
= 50 Hz
I I
I
I
A
s
CTs
CTp
50 50
10459
1
9000
1 162= × = × = .
EQUATION14059 V1 EN (Equation 25)
∠I
50s
= 0º
frequency of I
50s
= 50 Hz
It I
I
I
A
fs
CTs
CTp
tf= × = × =10459
1
9000
1 162.
EQUATION14062 V1 EN (Equation 26)
∠I
tfs
= 180º
frequency of I
tfs
= 49.5 Hz
Expected result: the protection function does not issue either start or trip.
The trajectory of the impedance traverses the lens characteristic in zone 2
Preliminary steady state test at 50 Hz
• Go to Main menu/Test/Function status/Impedance protection/
OutOfStep(78,Ucos)/OOSPPAM(78,Ucos):1/Outputs to check the available
service values of the function block OOSPPAM.
• Apply the following three-phase symmetrical quantities (the phase angle is related to
phase L1):
V V
V
V
V
ts t FwdZ
VT s
VT p
= × × = × × =0 9 0 9 11931
0 1
13 8
77 81. .
.
.
.
,
,
,
EQUATION14063 V1 EN (Equation 27)
Section 11 1MRK 504 165-UUS -
Testing functionality by secondary injection
158 Transformer protection RET670 2.2 ANSI
Commissioning manual
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