If the height or width of an object is known or drawn from a map,it’s distance will be defined by simply inverting the
calculation mentioned above the description in Point 13.
In other words ,if the width of an object with an angle of 8,is 1/7 of the distance according to the table 2 ,the same will
be reverse case , the distance is 7 times wider than the width or height.
Example 1:
A TV-tower is visible in the field and its height is known to be 200 m. The angle measured with the clinometer is 7°
from bottom to top of the tower.Column IV (gradient in %)indicates 12% for 7°.
100％ X 2000m (height of object)
OR 200m x 8(inversion of 1/8) =1600m
Example 2
The angle measured between object B and C (see figure) is
34°. The distance between B and C is 5 km according to
the map column IV ,Table 2 indicates 66%.
=7.5km OR 5km X 3/2 = 7.5km
When using this method,the object of known width must be
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