Condens 5000 W – 6720644146 (2019/03)
14
Flue lengths
5.4 Example for calculating the flue lengths (Fig. 9)
Installation analysis
Determine the following from the given installation situation:
• Method of routing the flue: vertical, Ø 80/125 mm
• Flue compliant with AS/NZ 5601: C
33
• Condensing boiler: ZSB 30-2 A
• length of horizontal flue: L
w
= 1 m
• length of vertical flue: L
s
= 6 m
• Number of 90 ° deviations in the flue: 2
• Number of 15 °, 30 ° and 45 ° deviations in the
flue: 0
Determining the parameters
Determine the parameters from table 6 as the flue is routed through a
duct compliant with C
33
. The following values result from ZSB 30-2 A:
•L
equiv,max
= 15 m
• equivalent length for 90 ° deviations: 2 m
• equivalent length for 15 °, 30 °and
45 °deviations: 1 m
Calculation of the equivalent pipe length L
equiv
The equivalent pipe length L
equiv
is calculated from the sum of the
horizontal and vertical flue lengths (L
w
, L
s
) and the equivalent lengths of
elbows. The required 90 ° elbows are included in the maximum lengths.
Take every additional deviation with its equivalent length into
consideration.
The equivalent total pipe length must be shorter than the maximum
equivalent pipe length: L
equiv
L
equiv,max
The equivalent total pipe length with 11 m is less than the maximum
equivalent total length of 15 m. As a result, the flue is OK.
Length/Number equivalent
partial length
Total length
straight length L
S
6 m × 1 = 6 m
straight length L
W
1 m × 1 = 1 m
90 ° elbow 2 × 2 m = 4 m
45 ° elbow 0 × 1 m = 0 m
equivalent pipe length L
equiv
11 m
Maximum equivalent pipe length L
equiv,max
15 m
L
equiv
L
equiv,max
o.k.
Table 8
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