CHAPTER 15 APPENDIXES
Capacity Selection Calculation 15-25
15
(1) Max. traveling speed (v)
If the reduction ratio is 1/1 and the rotation speed of the motor shaft is 3000 r/min
v = (3000/60) × 10×(1/1) = 500 mm/s
(2) Load inertia converted to motor axis (J
L)
Screw (J
1) Suppose Ø20 and 500 mm in length.
Moving parts (J
2) Suppose a transfer mass of 20 kg.
(3) Load torque converted to motor axis (T
L)
Suppose a transfer mass of 20 kg, friction coefficient (
µ) of 0.1 and machine efficiency (η) of 0.9.
= 0.6 × 10
-4
kg m
2
πρ
32
4
× GL
2
J
1
=
L
1000
π× 7.85 × 10
3
=
D
1
1000
32
500
1000
20
1000
4
× ( 1/1)
2
= 0.5 × 10
-4
kg m
2
2
× (GL)
2
J
2
= W
1
2π
= 20
BP
1000
× ( 1/1)
2
J
L = J
1
+ J
2
= 1.1 × 10
-4
kg m
2
2
1
2π
10
1000
× GL
T
L
=
(
µW + F) × 9.81
2π
η
BP
1000
× (1/1)
=
(0.1 × 20 + 0) × 9.81
2π × 0.9
10
1000
= 0.03 Nm
BP : Screw lead [mm]
D : Screw dia. [mm]
G
L
: Deceleration ratio
J
L
: Load inertia converted to motor
shaft [kgm
2
]
L : Screw length [mm]
T
L
: Load torque converted to motor
shaft [Nm]
W : Transfer weight [kg]
μ : Friction factor
×
×