CHAPTER 15 APPENDIXES
15-26
Capacity Selection Calculation
15
(4) Temporary selection
[Capacity selection condition]
①T
L
≤ T
R
× 0.9
T
L
= 0.03 Nm *P.15-26 (3)
②J
L
≤ J
M
× 10 (Frequent feed)
J
L
= 1.1 × 10
-4
kg m
2
*P.15-26(2)
The motor that satisfies the capacity selection condition (1) and (2) is:
GYS201D5-HB2 (0.2 kW)
(T
R
= 0.637 Nm, J
M
= 0.135 × 10
-4
kgm
2
, T
MAX
= 1.91 Nm)
(5) Shortest acceleration/deceleration time (t
AC)
Acceleration/Deceleration torque at an acceleration/Deceleration time of 0.05 seconds
(Mechanical efficiency (η) : assuming 100%)
[Acceleration torque]
[Deceleration torque]
T
AC
=
(J
M
+ J
L
) × 2π × N
60 (T
AC
- T
L
)
=
(0.135 × 10
-4
+ 1.1 × 10
-4
) × 2π × 3000
60 (1.91 - 0.03)
= 0.021 s
J
L
: Load inertia torque converted to motor shaft [kgm
2
]
J
M
: Motor inertia [kgm
2
]
T
AC
: Acceleration torque [Nm]
T
DC
: Deceleration torque [Nm]
T
L
: Load torque converted to motor shaft [Nm]
T
R
: Rated torque [Nm]
=
0.03 +
(0.135 × 10
-4
+ 1.1 × 10
-4
) × 2π × 3000
60 × 0.05
= 0.81 Nm
T
L
+ T
AC
=
(J
M
+ J
L
) × 2π × N
60 (t
AC
)
= 0.03 -
(0.135 × 10
-4
+ 1.1 × 10
-4
) × 2π × 3000
60 × 0.05
= -0.75 Nm
T
L
- T
DC
=
(J
M
+ J
L
) × 2π × N
60 (t
DC
)