KlY
in;
Ans_r;
KlY
in:
Answer;
300
m~rn(!!Ql
m
5
Content
of
MIImory 8
~
mm~rn!!!IDm
12
Contlnt
of Memory C
Acotllibll
m
....
ory
M;
•
81forl
1\8rting a calculation clear
the
memory
by
pressing
@1l!QI00
Key in:
12
rn
5~
Answer: 17
To
subtract
keV
in: 2
rn
5
~
~
Answer
to
this
Iquation:
7
Kev
in:
12
00
2
(!!Ql
DiD
5.
Formul.
Solution
in
thl
COMP MODE
Answer:
24
(Also lakes
plKI
of
10
in
memory)
To
solve
II
formulll using
the
memories as varillbies
In
the COMP MODE vou
must
first place
vour
villues
in
the
approp
rillte memories. Capacity
is
80
program steps for
plavback.
(Refer
to
"Direct Formula
Entry"
for a clatailed discussion of steps.)
Kev
in: 1 (gQ) m . 2
(!!Ql
rn
.
and
3
.:!!Ql
W
Kevin
:
/ii!fflrnrn~rnrn~m0
Answer: 6
Klvin
:
'
~rnMC±J~mIEJC±JMmIEJ0
Answer: 14
Kev in: {Mode ·
DEGI'S]ffi~m
rn~~rnrnl!!BJ~~m
Answer:
1.069251013
u.
of
memories
in
I
formul.
£len
memory
of this
calcul.tor
has.
storage
c.pecity
of 12 digits for m.ntilSll
.nd
of
2 digill for
exponent.
(11
In
the
entry
01
• formul
•.
pUShing
th.
~
CD
-
~
m .
~OO
recalls.
numerical
v.lul
nored
in a clasignated
memory
and
Uleli
it when
the
inputted
formula
is
axtc
uted
for calculation.
121
In
tha
e
ntry
of
a formula pushing a
~
rn
-
~
m .
[@oo
recalls
a numerical value
nored
in
the designated
memory
and
writal
it
into
the
formula.
In this case
the
numerical value
is
wrillen Into the formula in accordance with
Ihe designation of the decimal system.
21
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