So the external dimensions for the first part are ( see the second diagram on previous page):
13” Height x 44” Width x 9” Depth
We’ll go ahead and figure the volume of this enclosure (using internal dimensions). Subtract only one
thickness of wood from this height.
12.25 x 42.5 x 7.5 = 3904.68 cu.in.
3904.68 / 1728 = 2.25 cu. ft.
2.26 cu. ft. / 2 = 1.13 cu. ft. per driver
Notice that there is a 4” x 44” x 13” enclosure left over. This is just another airspace that we’ll figure vol-
ume for and add to the first part. ( Use internal dimensions!) Again, subtract only one thickness of wood
from this height.
3.25 x 42.5 x 11.5 = 1588.43 cu. in.
1588.43 / 1728 = 0.92 cu. ft.
0.92 cu. ft. / 2 = 0.46 cu. ft. per driver
Now, add 0.46 cu. ft to the first figure:
0.46 + 1.13 = 1.59 cu. ft. total per driver
This is your net internal airspace for each side of this
enclosure. That was not very tough, was it?
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