Specialized Concentrated Focused
Servo Motor「27」
7) Max. Velocity (Vmax)
max
Movement distance
Acc. times Dec. time
+ +Constant speed time
22
V
=0.3/0.9=0.334[m/s]
8) Rotational Speed
You need to convert it to N[r/min]. The guide travel per revolution of ball screw will be B
P
=0.02[m]
N=0.334/0.02=16.7[r/s]=16.7×60=1002[r/min]<3000[r/min] (Rated rotational speed of motor (0.2kW) )
9) Calculate the Torque
Constant Torque:
f
P 0.02
( gW+F)= 0.1 9.8 10+0
2 2 0.9
T
=0.035[N•m]
Acceleration torque:
a
( ) 2
Running torque
LM
psa
J J N
T
t
44
(1.73 10 0.14 10 ) 2 16.7
0.035
0.1
=0.196+0.035=0.231[N•m]
Deceleration torque:
d
( ) 2
Running torque
LM
d
ps
J J N
T
t
-
=0.196-0.035=0.161[N•m]
10) Confirm the Max. Torque
Acceleration torque =T
a
=0.231[N•m]<1.91[N•m] (the Max. torque of motor (0.2kW) )
11) Confirm the Effective Torque
2 2 2
2 2 2
0.231 0.1+0.035 0.8+0.161 0.1
=
2
a a f b d d
rms
c
T t T t T t
T
t
=0.067[N•m]<0.64[N•m] (the rated torque of motor (0.2kW) )
12) Confirm Motor Selection
Taking all calculations above into consideration, you can find that despite there is relatively large torque
allowance when choosing motor (0.2kW), it is a suitable choice considering inertia ratio.
3.5.2.2 Example of Motor Selection for Belt Driving System
1) Belt Driving System Structure: