So all bracing combined uses 250 cu. in. Now we’ll divide by 1728 to convert to cubic feet.
250 cu. in. / 1728 = 0.0289 cu. ft.
Now we go back to the enclosure volume figures we got after figuring driver displacement and deduct
brace displacement:
12” driver 1.72 - 0.0289 = 1.69 cu. ft.
10” driver 1.746 - 0.0289 = 1.717 cu. ft.
Result - we use 12” Kicker Comp VR woofers in a sealed enclosure! Another possibility though, is the 10”
Kicker Comp VR in a ported enclosure. It can be quite a long process to figure all these different things, but
trust us , going through all the trouble is worth it when you get done and have an enclosure that sounds
awesome!
Let’s say say you’re measuring a customer’s vehicle for available space and it’s basically unlimited in one
direction. If two dimensions are known and the other is unset, we have another way to calculate volume
for a specific speaker. For example, we’ll say the customer wants to use our Comp VR 12” driver. We know
that the recommended enclosure volume for a C12VR is 1.0 cu. ft., so for two it’s 2.0 cu. ft. Our two known
dimensions are 39.5” and 12.5” (internal). First we’ll find the total cubic inches on our known figures, just
multiply them together.
39.5” x 12.5” = 493.75 “
Next we need to figure the total cubic inches needed for two Comp VR 12’s. All we do is multiply 2.0
cu.ft. (recommended for two Comp VR12’s) by 1728 to convert to inches.
Now we divide the total cubic inches needed (3456) by the cubic inches that we have already (493.75) to
determine the missing dimension.
3456 / 493.75” = 6.999 inches for the depth
To check this, multiply all three figures:
39.5” x 12.5” x 6.999” = 3456 cu. in.
3456 / 1728 = 2.0 cu.ft.
Building an Angled Enclosure
To figure enclosure volume on angled boxes, draw a diagram
of your enclosure. It will help a lot to visualize what you’re
doing.
17” High x 54” Width x 5” Top Depth and 13” Bottom Depth
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