MASSEY FERGUSON 435X - Page 27

Introduction
01A01-20
MF 400 Xtra
01
8 - Flow rate
You have: You should To get:
- 1 l/min Multiply by 0.264 gallons per minute (gpm)
- 1 gpm Multiply by 3.788 liters per minute (l/min)
9 - Torque
You have: You should To get:
- 1 N.m Multiply by 8.851 pounds-force x inch (lbf.pol)
- 1 N.m Multiply by 0.738 pounds-force x foot (lbf.foot)
- 1 N.m Multiply by 10.0 kilograms-force x centimeter (kgf.cm)
- 1 lb.in Multiply by 0.113 newtons x meter (N.m)
- 1 lb.foot Multiply by 1.356 newtons x meter (N.m)
- 1 kgf.m Multiply by 7.239 pounds-force x foot (lbf.foot)
- 1 kgf.m Multiply by 86.8 pounds-force x inch (lbf.pol)
- 1 kgf.m Multiply by 9.81 newtons x meter (N.m)
- 1 N.m Multiply by 10.0 kilo. force x centimeter (kgf.cm)
- 1 kgf.cm Multiply by 0.10 newtons x meter (N.m)
- 1 N.m Multiply by 0.102 kilogram-meter (kgf.m)
- 1 N.m Multiply by 8.851 pound force (lbf.in)
- 1 lbf.in Multiply by 0.113 newtons x meter (N.m)
10 - Power
You have: You should To get:
- 1 hp Multiply by 735.7 watts (W)
- 1 hp Multiply by 0.9863 horse power (hp)
- 1 hp Multiply by 1.014 cv (or PS)
- 1 hp Multiply by 746 watts (W)
- 1 kW Multiply by 1.36 cv (or PS)
- 1 kW Multiply by 1.341 horse power (hp)
- 1 kW Multiply by 1000 watts (W)
11 - Temperature
You have: Use the formula: To get:
- ºC (ºC x 1,8)+32 ºF (Fahrenheit)
Examples: 50 ºC = 122 ºF -10 ºC = 14 ºF
- ºF 5/9 x (ºF - 32) ºC (Celsius)
Examples: 60 ºF = 15.5 ºC 49 ºF = 9.44 ºC
Note the coincidence: -40 ºF = - 40 ºC