Linear:%mathematically%consistent
Log:%perceptually%consistent
@#)A*)=D&>*5=[&@#A#()B&?5=E5D#(#9A&>5*&;#B=&)9,&.#,-5Q&48#*,&e,#(#59[&'(-H-&V*#A8(Q&;5$)B&F*-DD&0121/
K5A&D)=EB#9A&H)*#-D&(8-&B"=#9)9 $-&,#D()9$-&6-(7--9&D)=EB-D/&
48-*-&)*-&A*-)(-*&j"=ED&6-(7--9&D)=EB-D	 &(8-&8#A8B#A8(&)*-)D&
78-*-&7-&E-*$-#H-&B-DD&H)*#)(#59/