Vibe Space 12 D2 - Page 7

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I
f
we require a volume o
f
2
.5cu
f
t then we multipl
y
this b
y
17
28 2
.5 x 17
28
= 4
320
cubic inches
.
W
e now take
2
known enclosure dimensions that we will use, e.g height and width and divide this
f
igure b
y
them which will give us
the depth,
f
or example our hei
g
ht is 15”, our width is
20
”
.
S
o our de
p
th is 14.4”
f
or this enclosure
.
Note : this
f
ormula is
f
or the INTERNAL dimensions,
p
lease add the thickness o
f
the material used to construct the enclosure t
o
the
f
ormula to give
y
ou the outside dimensions.
S
o assuming we are using 1 inch material we need to add
2
thicknesses to each internal dimension to allow
f
or material top an
d
bottom
,
so the external dimensions
f
or this enclosure would be 17 x
22
x 1
6
.4 inches
.
The displacement o
f
the woo
f
er and the displacement o
f
the port must also be added to the required volume be
f
ore
y
ou calculat
e
the required sizes needed to build
y
our enclosure
.
N
O
TE- When using a port
y
ou must leave a gap at least equal to the shortest measurement o
f
the port between the rear o
f
th
e
enclosure and the
p
ort
.