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7
• Systems • Introduction
27
• Introduction
7 Selection procedure
7-1 Selection procedure System based on cooling load
7-1-3 Actual performance data
Use outdoor unit capacity tables
Determine the correct table according to the outdoor unit model and combination ratio.
Enter the table at given indoor and outdoor temperature and find the outdoor capacity and power input. The individual indoor unit capacity (power
input) can be calculated as follows:
ICA =
OCA x INX
TNX
ICA: Individual indoor unit capacity (power input)
OCA: Outdoor unit capacity (power input)
INX: Individual indoor unit capacity index
TNX: Total capacity index
Then, correct the indoor unit capacity according to the piping length.
If the corrected capacity is smaller than the load, the size of indoor unit has to be increased. Repeat the same selection procedure.
7-1-4 Selection example based on cooling load
1 Given
• Design condition
Cooling: indoor 20°CWB, outdoor 33°CDB
• Cooling load
• Power supply: 3-phase 380V/50Hz
2 Indoor unit selection
Enter indoor unit capacity table at:
20°CWB indoor temperature
33°CDB outdoor air temperature.
Selection results are as follows:
3
Outdoor unit selection
•Assume that the indoor and outdoor unit combination is as follows.
Outdoor unit: RXYQ10M
Indoor unit: FXCQ25M7 x 3, FXCQ40M7 x 5
•Indoor unit combination total capacity index
25 x 3 + 40 x 5 = 275 (110 %)
Room A B C D E F G H
Load (kW) 2.9 2.7 2.5 4.3 4.0 4.0 3.9 4.2
Room A B C D E F G H
Load (kW) 2.9 2.7 2.5 4.3 4.0 4.0 3.9 4.2
Unit size 25 25 25 40 40 40 40 40
Capacity 3.0 3.0 3.0 4.8 4.8 4.8 4.8 4.8
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