LG MULTI F A5UW40GFA0

2. Distributor type MULTI F DX (1 phase)
36 _ Heat pump 50Hz/R410A
Part 2 Product data_Outdoor units
3) Calculation of actual system capacity
① Outdoor unit rated capacity
Q
odu(rated)
[from specification table]
② Outdoor unit capacity at Ti, To temperature.
Q
odu(Ti, To)
[from capacity table]
③ Outdoor unit capacity coefficient factor
F
(T
i,
To)
= Q
odu(Ti, To)
/ Q
odu(rated)
④ Piping correction factor [from capacity coefficient factor table]
F
main (length, elevation)
for main piping length or elevation
F
branch (length, elevation)
for branch piping length or elevation
⑤ Individual indoor unit combinational capacity
Q
idu (combi)
= Q
odu(rated)
x Q
idu(rated)
/ Q
idu(rated-total)
⑥ Individual indoor unit actual capacity
Q
idu (actual)
= Q
odu(combi)
x F
(Ti, To)
x F
main (length, elevation)
x F
branch (length, elevation)
Example)
• Outdoor unit model : A7UW40GFA0 [FM40AH UO2]
• Total indoor units combination : 7k(A room) + .... + 9k = 48k
• Outdoor temperature : 39°CDB
• Indoor temperature : 19.5°CWB (A room)
• Main piping length (O/D to BD) : 40m
• Branch piping length (BD to I/D) : 10m (A room)
• Indoor unit actual cooling capacity in A room?
- Q
odu (rated)
: 11.2 kW
- Q
odu (Ti, To)
:
1) Combination ratio is calculated from capacity index in Btu/h
Total indoor capacity index / Outdoor unit cooling capacity
= 48 / 40 = 120%
2) From capacity table at T
i
, T
o
∴ Q
odu (Ti, To)
= 10.71 kW
- F
(Ti, To)
: 10.71 kW / 11.2 kW = 95.6%
- F
main (length, elevation)
= 89.8% (40m)
- F
branch (length, elevation)
= 98.0% (7k, 10m)
7k
- Q
idu(combi)
[7k] = 11.2kW x ––––– = 1.63 kW
48k
∴Q
idu(actual)
[7k] = 1.63 x 0.956 x 0.898 x 0.98
= 1.37 kW