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8.2. Capacity And Power Consumption
8.2.1. Cooling performance
Calculation of actual cooling capacity and power consumption:
Example: CS-F24DTE5 / CU-L24DBE5
• Calculation of the actual cooling capacity and power consumption for the following cooling conditions;
Indoor temperature of 27/19°C and outdoor temperature of 40°C (Standard condition).
Calculation method
1. Find the cooling capacity ratio and the power consumption ratio from the cooling capacity graph and power consumption graph for model CS-
F24DTE5 / CU-L24DBE5.
• The cooling capacity ratio indicate at the intersection between an outdoor unit air inlet temperature of 40°C on the horizontal axis and an
indoor unit air inlet temperature on 27/19°C is 0.95.
• The cooling power consumption ratio from the same intersection on the power consumption graph is 1.03.
2. Thus,
• Actual cooling capacity = cooling capacity ratio x rated cooling capacity = 0.95 x 6.5 = 6.18 (kw).
• Actual cooling power consumption = cooling power consumption x rated power consumption = 1.03 x 2.45 = 2.52 (kw).
Model name Max cooling capacity
Max capacity (kw) Max power consumption (kw)
CS-F24DTE5 / CU-L24DBE5 6.5 2.3
CS-F28DTE5 / CU-L28DBE5 7.5 2.45
CS-F34DTE5 / CU-L34DBE5 12 3.4
CS-F43DTE5 / CU-L43DBE5 13.5 4.3
CS-F50DTE5 / CU-L50DBE5 16 5.1
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