Water heat exchange unit
H - 25
8.
Position of center of gravity and earthquake resistance calculation
Bolt span
Short direction(l
1
)
l
1
= mm㩷
Long direction(l
2
)
l
2
= mm㩷
Actual strength of the foundation bolts
Short term allowable tensile stress(f
t
)
f
t
=㩷 176 㩷㩷N/mm
2
…㩷 for SS400 f
t
:176
Short term allowable shear stress (f
s
)
f
s
=㩷 99 㩷㩷N/mm
2
…㩷 for SS400 f
S6
: 132×0.75
Pull out load on one bolt
Short direction(R
b1
)
R
b 1
= 㩷㩷
㩷㩷
㩷㩷㩷㩷㩷㩷㩷㩷㩷㩷㩷㩷㩷㩷㩷
㩷㩷
㩷㩷=㩷 N
Long direction(R
b2
)
R
b 2
= 㩷㩷㩷㩷㩷㩷㩷㩷㩷㩷㩷㩷㩷㩷㩷㩷㩷㩷㩷㩷㩷㩷㩷=㩷㩷 N
Foundation bolt shear stress(
)
=㩷㩷㩷㩷㩷㩷㩷㩷㩷㩷=㩷㩷㩷N/mm
2
Foundation bolt tensile stress
Short direction(
1
)
1
=㩷㩷㩷㩷㩷㩷㩷㩷
㩷㩷
=㩷㩷㩷N/mm
2
Long direction(
2
)
2
=㩷㩷㩷㩷㩷㩷㩷㩷㩷㩷=㩷 㩷 N/mm
2
Allowable tensile stress in a bolt subject to simultaneous tensile and shear stress(f
ts
)
f
t s
=1.4 f
t
-1.6 =㩷 231.4㩷 N/mm
2
Judgment
Tensile load
Short direction䋺if R
b1
<T
a
OK R
b1
=㩷㩷<㩷 T
a
= 4 ,508
Long direction䋺if R
b2
<T
a
OK R
b2
=㩷㩷<㩷 T
a
= 4 ,508
Shear stress
if < f
s
㩷 OK =㩷㩷<㩷 f
s
=㩷 99
Tensile stress
short direction䋺 if
1
< f
t
<㩷 f
t
㩷
=㩷 176
㩷㩷㩷㩷㩷㩷㩷㩷㩷㩷㩷㩷㩷㩷㩷 㩷㩷㩷㩷 OK
1
=㩷 㩷
㩷㩷㩷㩷㩷㩷
1
< f
ts
<㩷 f
ts
=㩷 231.4
Long direction䋺if
2
< f
t
<㩷 f
t
㩷
=㩷 176
㩷㩷㩷㩷㩷㩷㩷㩷㩷㩷㩷㩷㩷㩷㩷 㩷㩷㩷㩷 OK
2
=㩷 㩷
㩷㩷㩷㩷㩷㩷
2
< f
ts
<㩷 f
ts
=㩷 231.4
F
H
h
h
G
–(W - F
V
)
l
G1
l
1
n
1
F
HG
- ( W-F
V
)
l
G2
l
2
n
2
F
H
NA
R
b 1
A
R
b 2
A
11
12
3
δ
δ
δ
δ
δ
δ
τ
τ
τ
δδ
δδ
ττ
Distance from center of gravity to bolt
Short direction(l
G1
)
l
G1
=㩷㩷 㩷mm㩷
Long direction(l
G2
)
l
G2
= 㩷 mm㩷
To Previous Page
Loading...
