Design
D - 20
■Calculate the effective inflow height, we (m) of each wall. Depending upon the wall height, and the flow in height
Ha the following two formulae apply.
For Hw
Ha : Hwe =(Ha-(H
U
+H
H
+Ht))×Xw+(H
U
+U
H
+Ht)×Xw×2
For Hw<Ha : Hwe =Ha-Hw+[Hw-
(H
U
+U
H
+Ht)]×Xw+(H
U
+U
H
+Ht)×Xw×2
here Hw : Wall height(m)
Xw : Wall opening fraction
•The wall height below the exhaust part (H
U
+U
H
+Ht) is
given twice
the weighting of other parts(inflow wind speed
0.5m/sJ1m/s).
•When there is no wall Hwe =Ha.
ii) Wall does not allow passage of air
■From the following formula, calculate the apparent height
Hb
1•2•3•4
(m) of each wall.
Hb = Hw-H
u
-1.5×Ht
Here, Hb: Apparent height of wall(m)
Hw: height of wall(m)
■For each wall, using the diagram on the right, obtain the effective
flow in height Hwe
1•2•3•4
(m) of each wall.
b)Calculate the effective flow in length Le
For the effective flow in height Hwe calculated for each wall,
calculate the effective flow in length Le
1•2•3•4
(m).
Calculate the effective length form each boundary surface (wall surface) to the nearest unit Lwei(m).
Calculate the effective flow in length of each wall Le
1•2•3•4
(m).
c) Calculate the effective flow in area
Using the effective flow in height Hwe
1•2•3•4
for each wall and the effective flow in length Le
1•2•3•4
calculated above,
obtain the effective flow in area of each wall.
i) Calculate the effective flow in area for each wall Se
1•2•3•4
(m).
ii) Calculate the overall effective flow in area Set(m
2
).
iii)Calculate the area of adjoining two surfaces.
when there is no wall : Lwei=6
For Lwi
6m : Lwei=6
For Lwi<6m : Lwei=Lwei
Le
1
=L
N
+Lwe
4
+Lwe
2
Le
2
=L
M
+Lwe
3
+Lwe
1
Le
3
=Le
1
Le
4
=Le
2
Se
1
=Hwe
1
×Le
1
Se
2
=Hwe
2
×Le
2
Se
3
=Hwe
3
×Le
3
Se
4
=Hwe
4
×Le
4
Se
12
=Se
1
+Se
2
Se
23
=Se
2
+Se
3
Se
34
=Se
3
+Se
4
Se
41
=Se
4
+Se
1
Apparent height of wall(m)
distance from the wall(m)
the effective flow in height
when there is no wall
Set=Se
1
+Se
2
+Se
3
+Se
4
5. Criteria for positioning the outdoor unit