WAGNER L606 - Page 39

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Determining Specic continued…
Example:
Length = 10 in. 10 in. / 12 in. = 0.833 ft.
Width = 7.5 in. 7.5 in. / 12 in. = 0.625 ft.
Thickness = 1.5 in. 1.5 in. / 12 in. = 0.125 ft.
Volume = L x W x T
0.833 x 0.625 x 0.125 = 0.065 cu. ft.
Weight = 20 oz. 20 oz. / 16 oz. = 1.25 lb.
Specic Gravity:
(Weight / Volume) / Specic Gravity of water
(1.25 lb. / 0.065 cu. ft.) / 62.34 lb. / cu. ft.
= 0.31
In order to ensure that the value obtained
for the specic gravity is statistically
signicant, a number of pieces must be
measured, and the average determined.
Use this value of specic gravity with the
table provided to nd the actual adjustment
factor for your species of wood.