3. Instruction Set
3-279
4. When n = 4, the bit structure will be as:
0 0 0 0 0 0 0 1 0 0 1 0 0 0 1 1
0 1
2 3
D10=0123 H
D20
D21
0 0 1 1 0 0 0 1 0 0 1 1 0 0 0 0
0 0 1 1 0 0 1 1 0 0 1 1 0 0 1 0
1
31H
0
30H
3
33H
2
32H
high byte
low byte
high byte
low byte
5. When n is 6, the bit structure will be as:
0 0 0 0 0 1 0 1 11 0 0 0000
0 0 0 0 1 0 0 1 0 1 1 11 1 1 0
0 1 1 0 1 0 1 1 0 1 00 1 1 0 1
0 1 2 3
D10
= H 0123
b15
b15
7 H 37
6 H 36
Converted to
b15
0 0 1 1 0 1 0 0 01 1 0 0000
0 1 1 0 0 1 0 0 0 0 1 00 1 1 1
b15
3 H 33
2 H 32
D22
b15
b0
b0
b0
b0
b0
D11 = H 4567
4 5 6 7
D20
D21
1 H 31 0 H 30
6. When n = 1 to 16:
K1 K2 K3 K4 K5 K6 K7 K8
D21 high byte
“3” “2” “1” “0” “7”
No
change
D25 low byte
D26 high byte