Jøtul F 600 - Alternate Floor Protection

ALTERNATE FLOOR PROTECTION
All floor protection materials must be non-combustible ie.
metal, brick, stone, mineral fiber boards). Any combustible
material may not be used.
The easiest means of determining if a proposed alternate
floor material meets requirements listed in this manual is
to follow this procedure.
R-value = thermal resistance
k-value = thermal conductivity
C-value = thermal conductance
1. Convert the specification to R-value;
a. If R-value is given, no conversion is
needed.
b. If k-value is given with a required
thickness (T) in inches: R=1/k X T.
c. If C-value is given: R=1/C.
2. Determine the R-value of the proposed alternate
floor protector.
a. Use the formula in Step 1 to convert
values not expressed as R.
b. For multiple layers, add R-values of each
layer to determine overall R-value.
3. If the overall R-value of the system is greater
than the R-value of the specified floor protector,
the alternate is acceptable.
EXAMPLE:
The specified floor protector should be 3/4 thick material
with a k-factor of 0.84. The proposed alternate is 4
brick with a C-factor of 1.25 over
1/8 mineral board witha k-factor of 0.29.
Step A. Use formula above to convert specifications to
R-value. R=1/k X T= 1/.84 X .75 = .893
Step B. Calculate R of proposed system.
4 brick of C-1.25, therefore
R brick = 1/C = 1/1.25 = 0.80.
1/8 mineral board of k = 0.29 therefore
R mineral board = 1/.29 X 0.125 = 0.431
Total R = R brick + R mineral board=
0.8 + 0.431=1.231
Step C. Compare proposed system R = 1.231 to
specified R of 0.893. Since R is greater than required,
the system is acceptable.
Definitions:
Thermal conductance =
C =
Btu = W
(hr)(ft
2
)(F) (m
2
)(K)
Thermal conductivity =
k =
Btu = W = (Btu)
(hr)(ft
2
)(F) (m
2
)(K) (hr)(ft)(F)
Thermal resistance =
R =
Btu = (m
2
)(K) = (Btu)(inch)
(hr)(ft
2
)(F) W (hr)(ft
2
)(F)
FOR THE JØTUL FIRELIGHT CB WOODSTOVE
REQUIRES FLOOR PROTECTION WITH A
MINIMUM INSULATING R VALUE OF 0.5.
ALCOVES REQUIRE AN R VALUE OF 1.6.
19