Midea MV5-X450W/V2GN1-AU - Unit Selection (Based on Cooling Load); Heating Capacity Modification

MCAC-VTSM-2015-10 R410A All DC Inverter V5 X Series 50Hz
Selection Procedure 17
data means outdoor unit is lower.
1.5.2 Heating capacity modification
2. Unit selection (based on cooling load)
2.1 Given condition
Condition:
Cooling: indoor temperature 20
o
C (68°F)WB, outdoor temperature 35
o
C(95°F)DB;
Cooling load
Location
Room A
Room B
Room C
Room D
Room E
Room F
Load kW
2.1
2.8
3.5
4.6
5.8
7.2
Power supply: outdoor 380~415V-3Ph-50Hz, indoor 220~240V-1Ph-50Hz.
Piping length: 50m; Height difference between indoor unit and outdoor unit: 30m
2.2 Indoor unit selection
Select the suitable capacity for the following conditions: ‘Indoor 20°C(68°F) WB, Outdoor 35°C(95°F) DB’ using
indoor unit capacity table. The selected result is as follows. (Assuming the indoor unit type is duct)
Location
Room A
Room B
Room C
Room D
Room E
Room F
Load kW
2.1
2.8
3.5
4.6
5.8
7.2
Model
22
28
36
45
56
71
Capacity kW
2.3
2.9
3.7
4.8
6.0
7.5
2.3 Outdoor unit selection
1) Assume the indoor unit and outdoor unit combination as follows
 Calculate the total nominal capacity of indoor units in the combination according to the above table:
2.2 × 1 +2.8 × 1+ 3.6 × 1 +4.5 × 1+ 5.6 × 1 + 7.1 × 1 = 25.8kW
 Select outdoor unit: MV5-X280W/V2GN1-AU which has nominal cooling capacity: 28kW.
 Calculate the proportion: 258/280= 92%
2) Result: Because the proportion is within 50～130%, it is a suitable selection.
Real function data with indoor unit combination
 For the 92% combination, calculate the cooling capacity of outdoor unit MV5-X280W/V2GN1-AU:
26.8kW←90% (Indoor temperature: WB 20°C, Outdoor temperature: DB 35°C)
28.3kW←100% (Indoor temperature: WB 20°C, Outdoor temperature: DB 35°C)
70
60
50
40
30
20
10
0
-10
-20
-30
-40
-50
-60
-70
-80
-90
-100
-110
10 20 30 40 50 60 70 80 90 100 110 120 130 140 150 160 170
L(m)
100%
99
98
97
95
96
93
H(m)
180
190
200
90
80
90
210
220