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❋ Table for current (Single installation)
Indoor unit Model Rated current (A) MCA ( A) MFA( A)
DVM Hydro unit
ADN✴✴✴BDE✴✴
AM✴✴✴FNBD✴✴
0.05 2.2 2.75
DVM Hydro unit HT
AM160FNBFE✴ 14.3 24.15 30.19
AM250FNBFE✴ 23.1 32.15 40.19
AM160FNBFG✴ 4.85 12.88 16.1
AM250FNBFG✴ 7.85 12.88 16.1
f ELB, MCCB capacity expression
X [A] = 1.25 X ∑Ai
❋ X [A] : ELB, MCCB capacity
❋ ∑Ai : Sum of each indoor unit's rated current
❋ Refer to each installation manual about the rating current of indoor unit.
f Decide the power cable specification and maximum length within 10 % power drop among indoor units.
n
∑(
k=1
Coef×35.6×Lk×ik
) < 10 % of input voltage[V]
1000×Ak
t coef : 1.55
t Lk : Distance among each indoor unit [m], Ak : Power cable specification [mm
2
]
ik : Running current of each unit [A]
Example of Installation
f Total power cable length L = 100(m), Running current of each units 1[A]
f Total 10 indoor units were installed
10[A]
Indoor unit 10
20[m]10[m]0[m]
9[A] 1[A]
100[m]
Indoor unit 2Indoor unit 1
ELCB
MCCB+
ELB
Or
f Apply following equation
n
∑(
k=1
Coef×35.6×Lk×ik
) < 10 % of input voltage[V]
1000×Ak
❋ Calculation
t Installing 1 type of wire.
220[V]
-2.2[V] -2.0[V]
············ 2.5[mm
2
] ············
208.8[V](Within 198 V~242 V)
-(2.2+2.0+1.8+1.5+1.3+1.1+0.9+0.7+0.4+0.2)=-11.2[V]
it's okay
2.5[mm
2
] 2.5[mm
2
]
t Installing with 2 different sort wire.
220[V]
-1.4[V] -1.2[V]
············ 2.5[mm
2
] ············
209.5[V](Within 198 V~242 V)
-(1.4+1.2+1.8+1.5+1.3+1.1+0.9+0.7+0.4+0.2)=-10.5[V]
it's okay
4.0[mm
2
] 4.0[mm
2
]
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