EasyManuals Logo

Gree GMV6 Series User Manual

Gree GMV6 Series
331 pages
To Next Page IconTo Next Page
To Next Page IconTo Next Page
To Previous Page IconTo Previous Page
To Previous Page IconTo Previous Page
Page #207 background imageLoading...
Page #207 background image
Gree GMV6 DC Inverter VRF Units Service Manual
205
2.2 Refrigerant charging amount B of every module
Refrigerant charging amount B
of every module (kg(Pounds))
Module capacity(kW)
IDU/ODU rated
capacity
collocation ratio C
Quantity of
indoor unit
22.4 28 33.5 40 45 50.4 56 61.5 68
50%≤C≤70%
<4
0
0
0
0
0
0
0
0
0
≥4
0.5(1.1)
1(2.2)
1(2.2)
1(2.2)
1(2.2)
0.5(1.1)
1(2.2)
1.5(3.3)
1.5(3.3)
70%
C≤90%
<4 0.5(1.1)
1(2.2) 1(2.2) 2(4.4) 2(4.4) 1.5(3.3)
2(4.4) 2(4.4) 2(4.4)
≥4
1(2.2)
1(2.2)
1(2.2)
2(4.4)
2(4.4)
2.5(5.5)
3(6.6)
3.5(7.7)
3.5(7.7)
90%
C≤105%
<4
1(2.2)
1(2.2)
1(2.2)
2(4.4)
2(4.4)
2.5(5.5)
3(6.6)
3.5(7.7)
3.5(7.7)
≥4
2(4.4)
2(4.4)
2(4.4)
4(8.8)
4(8.8)
4(8.8)
5(11.0)
5(11.0)
5(11.0)
105%
C≤135%
<4
2(4.4)
2(4.4)
2(4.4)
3(6.6)
3(6.6)
3.5(7.7)
4(8.8)
4(8.8)
4(8.8)
≥4 3.5(7.7)
4(8.8) 4(8.8) 5(11.0) 5(11.0)
5.5
(12.1)
6(13.2)
6(13.2) 6(13.2)
Notes:
Rated capacity configuration rate of indoor unit and outdoor unit C = sum of indoor unit rated
cooling capacity / sum of outdoor unit rated cooling capacity.
If all indoor units are all fresh air indoor units, the added refrigerant amount for each module B
is 0kg(0 LBS).
If all fresh air indoor units are mixed with the general VRF indoor units, charge the refrigerant
according to the refrigerant-charging method of the general indoor unit.
For example1:
Outdoor unit consists of one 28kW module and one 45kW module. Five 14kW duct type units are
used as indoor units.
IDU/ODU rated capacity collocation ratio C=14.0×5/(28.0+45.0)=96%. The quantity of included IDUs
is more than 4 sets. Please refer to the above table.
Additional refrigerant quantity B for 28kW module is 2.0 kg(4.41 LBS).
Additional refrigerant quantity B for 45kw module is 4 kg(8.82 LBS).
So, ∑Refrigerant charging amount B of every module=2.0+4=6 kg(13.23 LBS).
Suppose the Pipeline charging amount A=∑Liquid pipe length × refrigerant charging amount of every
1m liquid pipe=20kg(44.1 LBS).
Total refrigerant charging amount R=20+6=26kg(49.83 LBS).
For example 2:
Outdoor unit is a 45kW module and the indoor unit is a 45kW fresh air unit. The quantity (B) of
refrigerant added to this module is 0kg(0 LBS).
So, ∑Refrigerant charging amount B of every module= 0kg(0 LBS).
Suppose the Pipeline charging amount A=∑Liquid pipe length × refrigerant charging amount of every
1m liquid pipe = 5kg(11.025 LBS).
Total refrigerant charging amount R = 5+0=5kg(11.025 LBS).

Questions and Answers:

Question and Answer IconNeed help?

Do you have a question about the Gree GMV6 Series and is the answer not in the manual?

Gree GMV6 Series Specifications

General IconGeneral
BrandGree
ModelGMV6 Series
CategoryInverter
LanguageEnglish

Related product manuals