HP HP-15C - Go to

Section 3: Calculating in Complex Mode
95
Example: For the same potential as the previous example,
P(z) — 1/2 + 2, compute the velocity equipotential line starting at
z = 2 + i and proceeding to the left.
First change subroutine "B" so that it returns Re(P(2))—that is,
remove the |Re s Im | instruction from "B". Try n — 6 and h = -0.5.
(Notice that h is negative, which specifies that x^ will be to the left
ofx0.)
Although the keystrokes are not listed here, the results that would
be calculated and stored in matrix A are shown below.
*k
2.0000
1.8750
1.8672
1.8652
1.8647
1.8646
Vk
1 .0000
0.2362
0.1342
0.0941
0.081 1
0.0775
The results show the nature of the top branch of the curve (the
heavier dashed line in the graph for the previous example). Note
that the step size h is automatically decreased in order to follow the
curve—rather than stop with an error—when no y-value is found
for x< 1.86.