Kromschroder FCU 500 - Page 55

FCU 500, FCU 505 · Edition 02.17 55
Valve proving system
Calculation examples
2 valves VAS 665,
distance L = 9.5 m,
inlet pressure p
u
= 50 mbar,
max. flow rate Q
max.
= 200 m
3
/h.
FCU 500..C1
µC
P
131415
4758 48
TC
PZL PDZ
M
>750°
ϑ
1
2
3
V
p2
(300 l)
V3
V
p1
VAS 665 VAS 665
p
u
= 50 mbar
Q
max.
=
200 m
3
/h
DN65
9,5 m
Leakage rate Q
L
=
200 m
3
/h x 1000 l/h
= 200 l/h
1000 x 1 m
3
/h
Test volume V
p1
= 1.1 l + 9.5 m x 3.3 l/m = 32.45 l
see page 54 (Test volume Vp)
Test volume V
p2
= 300 l (assumed as an example)
Measurement time for one test volume V
p1
(between
2 gas solenoid valves or for system tightness)
Parameter 53 = 1 (between 2 gas solenoid valves),
parameter 53 = 2 (for system tightness, venting via V3),
parameter 70 = 0
t
M
[s] =
2 x 50 mbar x 32.45 l
= 16.23 s
200 l/h
Set the next highest value (20 s) using parameter 56,
see page 110 (Measurement time V
p1
).
Measurement time for two test volumes for system
tightness (V
p1
+ V
p2
)
Parameter 53 = 3, parameter 70 = 0
t
M
[s] =
2 x 50 mbar x (32.45 l + 300 l)
= 166.23 s
200 l/h
Set the next highest value (170 s) using parameter 57,
see page 110 (Measurement time V
p1
and Vp2).
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