20
Wiring Work (Continued)
Example of Installation
- Total power cable length L = 100(m), Running current of each units 1[A]
- Total 10 indoor units were installed.
10[A]
Indoor unit10
20[m]10[m]0[m]
9[A] 1[A]
100[m]
Indoor unit2Indoor unit1
Apply following equation.
∑ (
Coef×35.6×L
k×ik
) <
10% of input
voltage[V]
1000×A
k
n
k=1
Calculation
Installing with 1 sort wire
220[V]
-2.2[V] -2.0[V]
············ 2.5[mm
2
] ············
208.8[V](Within 198V~242V)
-(2.2+2.0+1.8+1.5+1.3+1.1+0.9+0.7+0.4+0.2)=-11.2[V]
it's okay.
2.5[mm
2
] 2.5[mm
2
]
Installing with 2 different sort wire
220[V]
-1.4[V] -1.2[V]
············ 2.5[mm
2
] ············
209.5[V](Within 198V~242V)
-(1.4+1.2+1.8+1.5+1.3+1.1+0.9+0.7+0.4+0.2)=-10.5[V]
it's okay.
4.0[mm
2
] 4.0[mm
2
]
ELCB
or
MCCB+
ELB
NASA_Big Duct_AM@@@FNHDEH@_IM_EN_03653A-06.indd 20 2016-12-01 오후 3:06:55