Operation
Passingawireo
ne time through the transformer core results in a single turn
secondary. To generate larger secondary signals, p ass the wire through the
transformer core multiple times.
To calculate how much voltage to apply to the CT-1 probe to inject a desired
amount of current, m ultiply the desired current to be injected by 5. For the CT-2
the voltage to apply is equivalent to the desired current. For example, if you want
to inject a 50 MHz signal that is 30 mA
P-P
using the CT-1, the amount of voltage
toapplyis30×5=150mV
P-P
. If you want to inject this same 30 mA
P-P
signal
with a CT-2
, the amount of voltage to apply is 30 mV
P-P
.
WARNING. To reduce risk of shock, ground the metal mounting stud.
WARNING. To reduce risk of RF burns, connect the probe to the circuit and signal
source before yo
u apply the stimulus signal.
CAUTION. Toreduceriskoffire and prevent damage to the probe, d o not exceed
the maximum in
jection voltage of 7 V
p-p
.
Low Frequency Response
The low-frequency response of the current transformer is proportional to the
inductance of the transformer windings. A DC component in the current being
measured tends to reduce this inductance. (See Figure 2.) (See Figure 3.)
You can also see this effect in the time domain. The pulse tilt is increased in the
presence of significant DC current. (See Figure 6.) The DC current required to
increase the tilt by a factor of two is about 0.3 A. Pulse currents that start at zero
and remain
unidirectional have a DC component that the user should consider.
Figure 6: CT-1 decay characteristics referenced to front corner
6 CT-1 and CT-2 Curr ent Transformer Instructions
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