Required Opening = CFM / 300 FPM
Example:
Given:
Qty of 4 units in a mechanical yard, surrounded by a fence. Units are 2TWR3048A1 -
Required:
Determine free air opening space required in fence -
Solution:
4400 CFM X Qty of 4 = 17,600 CFM
17600 CFM / 300 FPM = 58.67 square feet
Round 58.67 to 59 square feet of free air opening in the 4 fence sections surrounding the mechanical yard.
*Table produced August 2006. For the most current information, please refer to specific equipment Product
Data.
Pg. 19
XR13 and XR14 Outdoor Unit Airflow Table
2TTR3 / 2TWR3 2TTR4 / 2TWR4 4TTR3 / 4TWR3 4TTR4 / 4TWR4
Unit Model Number CFM Unit Model Number CFM Unit Model Number CFM Unit Model Number CFM
2TTR3018A1 1565 2TTR4018A1 2000 4TTR3018A1 3010 4TTR4018A1 2250
2TTR3024A1 2500 2TTR4024A1 2800 4TTR3024A1 3160 4TTR4024A1 2725
2TTR3030A1 3320 2TTR4030A1 3100 4TTR3030A1 3160 4TTR4030A1 2900
2TTR3036A1 4400 2TTR4036A1 3100 4TTR3036A1 3160 4TTR4036A1 3100
2TTR3042A1 4400 2TTR4042A1 4400 4TTR3042A1 4610 4TTR4042A1 4150
2TTR3048A1 4800 2TTR4048A1 4400 4TTR3048A1 4610 4TTR4048A1 4150
2TTR3060A1 4800 2TTR4060A1 4400 4TTR3060A1 4610 4TTR4060B1 4150
2TWR3018A1 1565 2TWR4018A1 2230 4TWR3018A1 3170
2TWR3024A1 2485 2TWR4024A1 2835 4TWR3024A1 3170 4TWR4024A1 2710
2TWR3030A1 2800 2TWR4030A1 3915 4TWR3030A1 3170 4TWR4030A1 3200
2TWR3036A1 4400 2TWR4036A1 4100 4TWR3036A1 4820 4TWR4036A1 4100
2TWR3042A1 4400 2TWR4042A1 4244 4TWR3042A1 4820 4TWR4042A1 4200
2TWR3048A1 4400 2TWR4048A1 4185 4TWR3048A1 4820 4TWR4048A1 4200
2TWR3060A1 4960 2TWR4060A1 4250 4TWR3060A1 4820 4TWR4060A1 4090
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