Chapter 2: Installation
Page 2–15SureServo2 User Manual – 1st Edition – 05/20/2021
Parameters DI/DO Codes MonitoringWiring Alarms
·
15000
SV2H-2B0N 338
428�37 155�93
SV2H-2B0B 346�5
SV2H-2F0N 451
570�91 155�93
SV2H-2F0B 461�8
Assume that the load inertia is N times the motor inertia, and when motor decelerates from
3000 rpm to 0, the regenerative power is (N+1) × E
0
and the regenerative resistor needs to
consume (N+1) × E
0
-E
c
joules. Assume that the reciprocate operation cycle is T sec, then the
required power of regenerative resistor is Watts = 2× ((N+1) × E
0
-E
c
) / T.
The calculation is as follows:
1
Set the wattage of the regenerative resistor to
the maximum�
Set P1�053 to the maximum value
2 Set the operation cycle (T) Manual input (T=seconds)
3 Set the rotation speed in RPMs (wr)
Manual input or read the status with P0�002
Code (09h)
4 Set the load / motor inertia ratio (N) Manual input or read the status with P0�002
5
Calculate the maximum regenerative resistor
(E
0
)
E
0
= J * wr2/182
Note, the value 182 comes from the formula
below:
/
(
/60)
6
Find the regenerative power that can be
absorbed by the capacitor (E
c
)
Refer to the table above
7
Calculate the required capacity (in Watts) of
the regenerative resistor
2 ×((N+1) × E
0
-E
c
) / T
Example 1:
For the motor SV2L-204B (400W), the reciprocating motion cycle is T = 0.4 sec.
Its maximum speed is 3000 rpm and the load inertia is 15 times of the motor inertia.
400 SV2L-204x 0�15 0�74 6�24
Find the maximum regenerative power: E
0
= 0.74 joules (from the table).
Find the regenerative power that can be absorbed by the capacitor; E
c
= 6.24 joules (from the
table).
The required capacity of the regenerative resistor =
2 x (N+1) x E
0
– E
c
T
Inserting the values for the variables gives:
2 x (15+1) x 0.74 – 6.24
0.4
= 43.6 W
From the calculation above, the required power of regenerative resistance is 43.6 W, which is
slightly greater than the specified capacity. In this case, a built-in 40W regenerative resistor
does not quite fulfill/ah the need. In general, the built-in regenerative resistor can meet the
requirement when the external load is not too great. The leading "2" in the equation is for
the protection of the resistor sizing and is why P1.053 is double what the drive uses for regen
calculations.
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