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Refrigerant piping
EXAMPLE OF SIZING OF REFRIGERANT PIPING
The example below illustrates the piping selection procedure for a system consisting of one outdoor unit (16HP) and
6 indoor units. The equivalent length of all the liquid pipes is greater than 90m; the pipe between the furthest indoor
unit and the first junction of the indoor joints is less than 20m; each internal auxiliary pipe (from each indoor unit to the
nearest joint) is less than 10m in length.
Unità interna
Unità esterna
L
1
L
2
N
1
N
2
N
3
N
5
N
6
N
4
L
3
L
4
L
5
primo giunto
a
A
B
D
E
C
b
c
e
f
d
(28)
(28)
(28)
(28)
(28)
(22)
(160)
Fig. 37
Select the main internal pipe
Refer to “Table 1” and “Table 2” to select the
internal auxiliary pipes (a-f).
Select the main internal pipes and the internal
branch joints B to I
The indoor units (N3 and N4) downstream of the
internal branch joint D have a total capacity of 2.8
+ 2.8 = 5.6kW. See “Table 1”. The main internal pipe
L4 is Ø15.9/ Ø9.5. The internal branch joint E is
FQZHN-01D.
The indoor units (N5 and N6) downstream of the
internal branch joint E have a total capacity of
2.8x2.2 = 5kW. Refer to “Table 1”. The main internal
pipe L4 is Ø15.9 / Ø9.5. The internal branch joint D
is FQZHN-01D.
The indoor units (N3 and N6) downstream of the
internal branch joint C have a total capacity of
2.8x3+2.2kW= 10.6kW. Refer to “Table 1”. The main
internal pipe L3 is Ø15.9 / Ø9.5. The internal branch
joint C is FQZHN-01D.
The indoor units (N1 and N2) downstream of the
indoor branch joint B have a total capacity of
2.8x2= 5.6kW. Refer to “Table 1”. The main internal
pipe L2 is Ø15.9 / Ø9.5. The internal branch joint B
is FQZHN-01D.
Select the main pipe and the internal branch
joint A
The indoor units (from N1 to N6) downstream
of the internal branch have a total capacity of
2.8x5+2.2kW=16.2kW. The total sequential length
of the system is less than 90 m. The total capacity
of the outdoor unit is 16HP. Refer to “Table 1” and
“Table 2”. The main pipe L1 is Ø15.9 / Ø9.5 and the
internal branch joint A is FQZHN-01D.
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