FATEK FBs-B2DA - Page 51

H5-8
Result: (1) First calculate current consumption of internal 5VDC logic power supply
+722mA - 120mA - 223mA - 119mA - 40mA - 40mA - 25mA = +155 mA (OK)
(2) And then calculate current consumption of internal 24VDC logic power supply
+325mA - 124mA - 136mA - 136mA = -71 mA (overload)
(3) Calculate current consumption of external 24VDC Sensor power supply
+295mA - 162mA - 53mA = +80 mA (OK)
In conclusion, the total current consumption of internal 24VDC logic power supply of above six expansions exceeds
power capacity of the main unit, so needs to expand power supply module as in example 3.
Example 3:
The below diagram is a system modules, try to calculate the power supply used of the system.
Result Result
Internal 5VDC
logic power
supply
-120 -223
+722 -119 -40 -25 +195 (OK) 400 -40 +360(OK)
Internal 24VDC
logic power
supply
－ －
+325 -124 -136 － +65 (OK) 250 -136 +114 (OK)
External 24VDC
Sensor power
supply
－ －
+295 -162 － -53 +80 (OK) 250 － +250 (OK)
Result: (1) First calculate the current consumption of expansion modules which provided from
the main unit.
current consumption of internal 5VDC logic power supply
+722mA - 120mA - 223mA - 119mA - 40mA - 25mA = 195mA (OK)
current consumption of internal 24VDC logic power supply
+325mA - 124mA - 136mA = 65 mA (OK)
current consumption of external 24VDC Sensor power supply
+295mA - 162mA - 53mA = 80 mA (OK)
(2) then calculate the current consumption of expansion modules which provided from
expansion power supply module
current consumption of internal 5VDC logic power supply
+400mA - 40mA = +360 mA (OK)
current consumption of internal 24VDC logic power supply
+250mA - 136mA = +114 mA (OK)
current consumption of external 24VDC Sensor power supply
+250mA - 0mA = +250 mA (OK)
In conclusion, add one expansion power supply(FBs-EPW-AC)，in this way it can satisfy the total current
consumption of six expansion modules.
(1) (2)
FBs-
EPW-AC
Unit : mA
FBs-
CM55E
FBs-
B2DA
FBs-
24MC
FBs-
60XYR
FBs-
16YR
FBs-
6AD
FBs-
16YR