HP HP-15C

136 Section 11: Calculating With Complex Numbers
Keystrokes
Display
2 ´ }
0.0000
2i. Display shows real part.
8 “ v
-8.0000
6 ´ V
-8.0000
-8 + 6i.
3 Y
352.0000
(-8 + 6i)
3
.
*
-1.872.0000
2 i (-8 + 6i)
3
.
4 v
4.0000
5 ¤
2.2361
2 “ *
-4.4721
52
.
´ V
4.0000
i524
.
÷
-295.4551
i
ii
5 2 - 4
3
)6 (-82 
.
2 v 5 ¤
2.2361
4 “ *
-8.9443
´ V
2.0000
i542
.
÷
9.3982
Real part of result.
´ %
-35.1344
Answer: 9.3982 -35.1344i.
9.3982
2.
Write a program to evaluate the function
35
12



z
z
ω
for different
values of z. (
ω
represents a linear fractional transformation, a class of
conformal mappings.) Evaluate
ω
for z = l+2i.
(Answer: 0.3902 + 0.0122i. One possible keystroke sequence is: ´
b A v v 2 * 1 + ® 5 * 3 + ÷
¦ ´ } | n.)
3.
Try your hand at a complex polynomial and rework the example on
page 80. You can use the same program to evaluate P(z) = 5z
4
+ 2z
3
,
where z is some complex number.
Load the stack with z = 7 + 0i and see if you get the same answer as
before. (Answer: 12,691.0000 + 0.0000i.)
Now run the program for z = 1 + i. (Answer -24.0000 + 4.0000i.)