EasyManuals Logo
Home>Midea>Air Conditioner>V6-i Series

Midea V6-i Series User Manual

Midea V6-i Series
118 pages
To Next Page IconTo Next Page
To Next Page IconTo Next Page
To Previous Page IconTo Previous Page
To Previous Page IconTo Previous Page
Page #20 background imageLoading...
Page #20 background image
V6-i VRF 50Hz
19
c) Find the correction factor for piping length and level difference (“K1”)
Figure 1-5.4: V6-i rate of change in cooling capacity
Notes:
1. The horizontal axis shows equivalent length of piping between farthest indoor unit and outdoor
unit; the vertical axis shows the largest level difference between indoor unit and outdoor unit.
For level differences, positive values indicate that the outdoor unit is above the indoor unit,
negative values indicate that the outdoor unit is below the indoor unit.
d) Calculate the corrected capacity of MVi-280WV2RN1(A) (“C”) by using K1:
C = B × K1 = 30.01 × 0.898 =26.95kW
The corrected capacity 26.95 kW is larger than required total heat load 26.5kW, so selection is complete.
50
40
-40
30
-30
20
-20
10
1.0
0.97
0.95
0.92
0.90
0.87
0.85
0.84
0.81
1.0
0.97
0.95
0.92
0.90
0.87
0.85
0.84
10 20 30 40 50 60 70 80 90 100 110 120
-10
0
0
L(m)
H(m)

Other manuals for Midea V6-i Series

Questions and Answers:

Question and Answer IconNeed help?

Do you have a question about the Midea V6-i Series and is the answer not in the manual?

Midea V6-i Series Specifications

General IconGeneral
BrandMidea
ModelV6-i Series
CategoryAir Conditioner
LanguageEnglish

Related product manuals