DC inverter ARV Individual Series technical manual
81
Select the suitable capacity for condition of ‘Indoor 21°C (WB), Outdoor 35°C (DB)’ using indoor
unitcapacity table. Because of the long pipelines and large height difference between indoor and outdoor
unit, we consider choosingindoor unit of a largernominal cooling capacity.
The selected result is as follow:
(3) Outdoor unit selection
Calculate the total nominal coolingcapacity of indoor units in the combination according to the above
table:
2.5×3+11.2×3 +5.6×3+7.1×3=79.2 kW
Select outdoor unit:ARV-H30/R1MI, which has nominal cooling capacity: 85kW.
The combination ratio between indoor units and outdoor unit: 79.2/85×100% = 93.2%
Result : Because the ratio is within 50~130%, we can go to next step.
(4) Outdoor unit capacity correction
a. Assuming the combination of indoor and outdoor units is as follow:
Outdoor unit: ARV-H26/R1MI
Indoor unit: ARVLD-H028/4R1A, 7×ARVMD-H100/4R1A, 2×ARVMD-H056/4R1A,
b.For the 99% combination, calculate the cooling capacity of outdoor unit.
83.77kW ←90% (Indoor temperature: WB 21°C, Outdoor temperature: DB 35°C)
87.76kW ←100%(Indoor temperature: WB 21°C, Outdoor temperature: DB 35°C)
Then calculate the outdoor capacity in 99% combination index:
Therefore: 83.77 + {(87.76-83.77)/10} × 9= 84.17;
c. The capacity modification coefficient with pipe length (30m) and height difference (10m) (Outdoor unit
is lower than indoor units):0.88.
Then calculated the outdoor capacity: 84.17×0.88=74.07kW
(5) Indoor unit capacity correction
The individual indoor unit capacity (power input) can by calculated as follows.
IUC=OUC × INX/TNX
IUC: Each indoor unit capacity
OUC: Outdoors unit capacity
INX: Each indoor unit capacity index