AUX ANB66FVAMT - Page 84

DC inverter ARV Individual Series technical manual
81
Select the suitable capacity for condition of ‘Indoor 21°C (WB), Outdoor 35°C (DB)’ using indoor
unitcapacity table. Because of the long pipelines and large height difference between indoor and outdoor
unit, we consider choosingindoor unit of a largernominal cooling capacity.
The selected result is as follow:
Room A
Room B
Room C
Room D
Cooling load (kW)
2.2
9.5
5.3
6.0
Unit specification
25
112
56
71
Capacity (kW)
2.5
11.2
5.6
7.1
(3) Outdoor unit selection
Calculate the total nominal coolingcapacity of indoor units in the combination according to the above
table:
2.5×3+11.2×3 +5.6×3+7.1×3=79.2 kW
Select outdoor unit:ARV-H30/R1MI, which has nominal cooling capacity: 85kW.
The combination ratio between indoor units and outdoor unit: 79.2/85×100% = 93.2%
Result : Because the ratio is within 50～130%, we can go to next step.
(4) Outdoor unit capacity correction
a. Assuming the combination of indoor and outdoor units is as follow:
Outdoor unit: ARV-H26/R1MI
Indoor unit: ARVLD-H028/4R1A, 7×ARVMD-H100/4R1A, 2×ARVMD-H056/4R1A,
b.For the 99% combination, calculate the cooling capacity of outdoor unit.
83.77kW ←90% (Indoor temperature: WB 21°C, Outdoor temperature: DB 35°C)
87.76kW ←100%(Indoor temperature: WB 21°C, Outdoor temperature: DB 35°C)
Then calculate the outdoor capacity in 99% combination index:
Therefore: 83.77 + {(87.76-83.77)/10} × 9= 84.17;
c. The capacity modification coefficient with pipe length (30m) and height difference (10m) (Outdoor unit
is lower than indoor units):0.88.
Then calculated the outdoor capacity: 84.17×0.88=74.07kW
(5) Indoor unit capacity correction
The individual indoor unit capacity (power input) can by calculated as follows.
IUC=OUC × INX/TNX
IUC: Each indoor unit capacity
OUC: Outdoors unit capacity
INX: Each indoor unit capacity index