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Honeywell F57A User Manual

Honeywell F57A
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F57A,B FLUSH-MOUNT COMMERCIAL ELECTRONIC AIR CLEANER
5 68-0083—07
Fig. 3. F57 sizing by air changes per hour and room area. In most cases, one F57B is equivalent to half an F57A because
the F57B airflow, although less than 50 percent of F57A airflow, is more effectively applied via several locations.
EXAMPLE 1:
Sizing by air changes per hour and room area (using the
graph in Fig. 3).
An office measures 40 x 45 ft (12 x 14m). How
many F57 air cleaners should be installed?
SOLUTION:
1. Find the floor area.
40 ft x 45 ft = 1800 ft
2
(12m x 14m = 168m
2
).
2. Assuming ten air changes per hour, with an 1800 ft
2
(168m
2
) area, the graph (Fig. 3) indicates a require-
ment for two F57A units, or four F57B units.
EXAMPLE 2:
Sizing by occupant load.
A cocktail lounge averages 75 occupants. How
many F57 air cleaners should be installed?
SOLUTION:
Number of F57s required =
ASHRAE Recommended Air Circulation/Min
F57 Capacity
1. ASHRAE recommended minimum air circulation is
35 cfm (1m
3
/min) per person. For 75 people, the rec-
ommended air circulation would be:
75 people x 35 cfm (1m
3
/min) per person = 2625 cfm
(75m
3
/min).
2. F57A capacity (HI setting) is 1030 ft3/min
(29m
3
/min).
Number of F57As required =
2625 ft
3
/min/1030 ft
3
/min = 2.5 or 3 units.
or
F57B capacity (HI setting) is 485 cfm (14m
3
/min).
Number of F57Bs required =
2625 ft
3
/min/485 ft
3
/min = 5 units.
EXAMPLE 3:
Sizing by air changes per hour and room volume.
A shop proprietor wants to use electronic air clean-
ing to remove high levels of smoke from the air. The
shop is 25 x 40 ft (8 x 12m) with a 15 ft (4.5m) ceil-
ing. How many F57 air cleaners will be required?
GUIDELINE: In the absence of other information, select the
correct number of F57 units to provide between 10 or 20
air changes per hour, depending on contaminant level. The
air cleaner should be located directly above or as close as
possible to the source of contamination.
SOLUTION:
Number of F57s required =
Desired Air Circulation/Min
F57 Capacity
1. Calculate the volume of the room.
25 ft x 40 ft x 15 ft = 15,000 ft
3
(8m x 12m x 4.5m = 432m
3
).
2. Determine the volume of air to be circulated each
hour. Ten air changes per hour are used here on the
assumption that the intent is to reduce, but not com-
pletely eliminate, smoke.
15,000 ft
3
x 10 air changes per hour = 150,000 ft
3
/hr
(432m
3
x 10 air changes per hour = 4320m
3
/hr).
Then determine the volume of air to be circulated
each minute.
150,000 ft
3
/hr
60 min/hr = 2500 ft
3
/min
4320 m
3
/hr
60 min/hr = 72m
3
/min
3. F57A capacity (HI setting) is 1030 ft
3
/min
(29m
3
/min).
Number of F57As required =
10
9
8
7
6
5
4
3
2
1
20
18
16
14
12
10
8
6
4
2
EXAMPLE 1
537
(50)
1075
(100)
1610
(150)
2150
(200)
2690
(250)
3230
(300)
3760
(350)
4300
(400)
AREA IN SQUARE FEET (SQUARE METERS)
TO USE THE GRAPH:
EXTEND A HORIZONTAL LINE FROM THE DESIRED NUMBER OF AIR CHANGES PER HOUR, UNTIL IT INTERSECTS
WITH A VERTICAL LINE DRAWN UPWARD FROM THE NUMBER OF SQUARE FEET OF THE ROOM.
READ THE NUMBER OF UNITS REQUIRED AT THE INTERSECTION POINT.
1.
2.
25
20
15
10
5
0
BOWLING
CENTERS
PLACES OF
ASSEMBLY
STORES
OFFICES
RESTAURANTS
BARS
CAFETERIAS
LUNCHEONETTES
AIR
CHANGES
PER HOUR
F57A UNITS REQUIRED
F57B UNITS REQUIRED
M1206B

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Honeywell F57A Specifications

General IconGeneral
BrandHoneywell
ModelF57A
CategoryAir Cleaner
LanguageEnglish

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