2 fR/sl S=0.7834 x = 2. Starts integrat
ing
and
produces the
result for
Jff
fit).
To complete the calculation, remember to multiply the value of the
integral by the constant (1/ir) outside the integral.
(You
could also in
clude this multiplication as
part
of the program.)
BH
(T) 0.2239 Final result for /0(2).
Now calculate /0(3) with the same limits of integration. You don't
have to respecify the function (routine J), but you must respecify the
limits of integration (0,
ir)
since they were pushed off the stack by the
subsequent division by tt.
0 1ENTER
IM*|
3.1416
X72.0000
Displays
upper
lii
HI
SOLVE//
|
{/FN}
T
Starts integration;
prompts for x.
3|R/S|
,T=-0.8170
Integral of fit).
10
0
-0.2601
Result for /0(3).
Example:
Sine
Integral. Certain problems in communications the
ory (for example, pulse transmission through idealized networks)
require calculating an integral (sometimes called the
sine
integral)
of
the
form
Si(t)
X'fr)*
Find Si(2).
Key in the following program to evaluate the function
fix) = (sinx)
-5-
x.*
*If the
calculator
attempted
to
evalutate
this
function
atx = 0, the
lower
limitof
integration,
an
error
(DIVIDE BY 8) would
result.
However,
the
integration
algorithm
normally does
not
evaluate
functions at eitherlimit of
integration,
unlessthe endpointsof the
interval
of
integration
are
extremely
close
together
or the number of
sample
pointsis
extremely
large.
130
8:
Numerical
Integration
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