It's apparent from inspectingthe equation that if x is a negativenum
ber, the smallest that
/fa)
can be is 10.
/fa)
approaches
10 as x becomes
a negative number of large magnitude.
Example: A Math
Error.
Find the root of the equation:
\j[x
-f-
(x +
0.3)]
- 0.5
Enter the function as the program:
101
LBL
I
102
RCL
X
103
0.3
104
RCL+
X
105
-r
106
SQRT
107
0.5
108
-
109
RTN
First attempt to find a positive root.
Keys:
Display:
•I
SOLVE/J
|
{FN}
I
orsToix
10
11
SOLVE/J
| {SOLVE}
X X=
0.1000
0.
Description:
Calculates
the
root
us
ing guesses 0
and
10.
Now attempt to find a negative root by entering guesses 0 and
—10.
Notice
that
the
function
is
undefined
for
values
of
x
between
0
and
—0.3
since those values produce a positive denominator but a nega
tive numerator, causing a negative square root.
OfSTQlX 10
[J73
Bl
SOLVE/J
| {SOLVE}
X
Ml
VIEW
| X
SQRT(NEG)
X=-0.1308
270
C:
More
About
Solving
an
Equation
Math
error.
Displays the final esti
mate
of
x.
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