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IBM 5100 - Page 177

IBM 5100
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c
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Storage Considerations
The following list shows
how
many bytes
of
storage are required for each
data
type
that
can be
in
the
active workspace:
Data
Type
Character
constant
or
variable name
Whole numbers
that
are equal
to
or
less
than
2
31
_1
Whole numbers
that
are greater
than
2
31
_1
Decimal numbers
Logical data
Number
of
Bytes Required
1 byte per
character
4 bytes
8 bytes
8 bytes
1/8
byte
(1
byte
can
contain
8
ones
or
zeros)
Because
the
5100
active workspace
contains
a fixed
amount
of
storage, it
is
good
practice
to
conserve
as
much storage as possible. Following are some considera-
tions
that
can be used
to
conserve storage:
Make all objects (variables and user-defined functions)
not
required for use
out-
side of a user-defined
function
local
to
the
function.
Store data
in
data files
on
the
tape,
and use an APL shared variable (see
Chapter 8)
to
transfer
the
data
into
the
active workspace when required.
Clear suspended functions (see Chapter 7) from
the
active workspace.
Group
user-defined functions by related operations
and
store
each
group
into
a workspace file on tape. Then when a certain
group
of
related
functions
is
required
to
process data
in
the
active, workspace,
the
stored workspace contain-
ing these functions can be copied
into
the
active workspace. When
the
pro-
cessing
is
done,
the
functions can be
expung~d
(see Chapter 5) and
another
group
of
functions (one workspace) can be copied
into
the
active workspace.
If a value consists
of
all
1's and D's, store
the
value as logical data.
For
example,
you
have
the
following vector: .
VECTOR~"l
0 p (2·-:1.)
VECTOR
1
111
111
1 1 1
The
result
is
a vector
of
ten
l's,
and
each 1 requires
four
bytes
of
storage.
However,
the
vector can be changed
to
a logical vector as follows:
VECT[)R~"lAVECTDr~
VECT()I~
1 1 1 1
111
111
The result looks just like
the
previous result; however, only 2
bytes
of
storage
was required.
173

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