6 Rockwell Automation Publication 5069-IN019C-EN-P - October 2018
CompactLogix 5480 Controller
Spacing
Maintain spacing from enclosure walls, wireways, and adjacent
equipment. Ambient temperature is higher at the top of an enclosed
cabinet.
The minimum distance on of a system that includes only a
CompactLogix 5480 controller is as follows:
• 25.00 mm (0.98 in.) between the sides and the cabinet
• 25.00 mm (0.98 in.) between the front of the controller and
the cabinet
• 50.00 mm (1.96 in.) between the top and bottom and
the cabinet
We recommend that you install the controller near the bottom
of the enclosure, where ambient temperature is lower.
Enclosure Selection
This example is provided to help you size an enclosure for your
CompactLogix 5480 controller. You need heat dissipation data from
all components that are planned for your enclosure to calculate the
enclosure size.
With no active method of heat dissipation, for example, air
conditioning, either of the following approximate equations can be
used for a metal cabinet.
The maximum ambient rating of the CompactLogix 5480 controller
is 60 °C (140 °F). If the maximum external cabinet temperature is
20 °C (68 °F), then T=40.
In this example, with only the controller, the heat dissipation is 72 W,
that is, the sum of all components in the enclosure. In the following
equation, T=40 and Q=72.
In this example, the enclosure must have a minimum exterior surface
of 0.386 m
2
.
If any portion of the enclosure cannot transfer heat, exclude that value
from the calculation.
The minimum installation clearance for a CompactLogix 5480
controller is 267.00 x 184.00 x 152.00 mm (10.50 x 7.25 x 6.00 in.)
HxWxD.
The standard cabinet depth in this example is 154.20 mm (6.00 in.).
To meet cooling and clearance requirements in this example, the
cabinet must be approximately 304.80 x 355.60 x 154.20 mm
(12.00 x 14.00 x 6.00 in.) HxWxD.
A = 2DW +2DH + 2WH
A = 2 x (0.1542 x 0.3556) + 2 x (0.1542 x 0.3048) +
2 x (0.3556 x 0.3048) = 0.4204 m
2
Top
Bottom
SideSide
End cap
Cabinet
Metric Imperial
Where:
• T = Temperature difference between
inside air and outside ambient (°C)
• Q = Heat that is generated in enclosure
(Watts)
• A = Enclosure surface area (m
2
)
Where:
• T = Temperature difference between
inside air and outside ambient (°F)
• Q = Heat that is generated in enclosure
(Watts)
• A = Enclosure surface area (ft
2
).
The exterior surface of all six sides of an
enclosure is calculated as:
A = 2dw + 2dh + 2wh
Where d (depth), w (width), and h (height)
are in meters.
The exterior surface of all six sides of an
enclosure is calculated as:
A = (2dw + 2dh + 2wh) /144
Where d (depth), w (width), and h (height)
are in inches.
0.38Q
1.80T - 1.10
A =
4.08Q
T - 1.10
A =
0.38(72.00)
1.80(40.00) - 1.10
A =
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