BRUEL & KJAER 2626 - Page 10

Since A (the open loop gain of the amplifier), is very large, then usually
so the output becomes
-Q
Hence if C
1
remains constant, the output voltage is directly proportional
to the charge appearing across the accelerometer and the cable capacitance
Cc normally has a negligible effect. Only when Cc becomes comparable to
AC
1
will it affect the gain.
8