33
32
B.General Calculation Functions
1) Multiplication
Example : 20 x 15
Operation : Align "20" on the outer scale with "10" on the inner scale. Then, "15" on the
inner scale corresponds to "30" on the outer scale. Take into account the
position of the decimal point and add one zero to obtain 300. Note that with
the scales of this watch, the position of the decimal point cannot be ob-
tained.
2) Division
Example : 250 / 20
Operation : Align "25" on the outer scale with "20" on the inner scale. Then, "10" on the
inner scale corresponds to "12.5" on the outer scale. Take into account the
position of the decimal point to obtain 12.5.
3) Proportion
Example : 30/20 = 60/x
Operation : Align "30" on the outer scale with "20" on the inner scale. Then, "60" on the
outer scale corresponds to "40" on the inner scale. At this point, the propor-
tion for every value on the inner and outer scales is 30 :20.
The same method can be applied to the conversions of U.S. gallons→fuel
pound, IMP. gallons, liters / IMP. gallons→fuel pound, U.S. gallons, liters /
liters→fuel pound, IMP. gallons, U.S. gallons.
13) Volume - weight conversions (oil pounds to U.S. gallons, IMP gallons and liters)
Example : Convert 16. 4 oil pounds into U. S. gallons, IMP. gallons and liters. (1 oil
pound=0. 133 U. S. gallons, =0. 111IMP. gallons, =0. 503 liters)
Answer : Align"16. 4"on the inner scale with U. S. GAL. (▲)on the outer scale. Then,
U. S. GAL. (▲)on the outer scale corresponds to "21. 8(2. 18 U. S. gallons)"on
the inner scale. Then, IMP. GAL. (▲)on the outer scale corresponds to"18.
2(1. 82 IMP. gallon)"on the inner scale, and LITERS. (▲)on the outer scale
corresponds to "82. 7(8. 27 liters)"on the inner scale.
The same method can be applied to the conversions of U.S. gallons→oil
pound, IMP. gallons, liters / IMP. gallons→oil pound, U.S. gallons, liters /
liters→oil pound, IMP. gallons, U.S. gallons.
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