HP 39G

293
S
S
o
o
l
l
u
u
t
t
i
i
o
o
n
n
o
o
f
f
m
m
a
a
t
t
r
r
i
i
x
x
e
e
q
q
u
u
a
a
t
t
i
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o
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n
n
s
s
Solve for the value of X in
(2)
A
IXB
−
=
where
23 3 2
,
15 1 4
AB




−
==
−
Store the values of A
and B into M1 and M2 respectively.
Finally use the HOME view to calculate the
answer, using the function IDENMAT(2) to
produce a 2x2 identity matrix, and making sure
to store the result into M3.
In this case the result is a horrible decimal.
The fractional equivalent can be found by
setting the MODES view to Decimal 6 and then
re-evaluating, as shown right. From this it can
be seen that the common denominator seems
to be 26, so multiplying M3 by 26 will give a
final result of:
122
57
X

=

−

()
1
1
1
(1 2 )
12
2
1
2
AXB
XAB
XABI
X
AB I
−
−
−
−
=
−=
−= −
−
=
−