Mitsubishi PUHY-P250YJM-A - Page 117

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HWE1018A GB
3. Amount of refrigerant to be added
The amount of refrigerant that is shown in the table below is factory-charged to the outdoor units.
The amount necessary for extended pipe (field piping) is not included and must be added on site.
(1) Calculation formula
The amount of refrigerant to be added depends on the size and the length of field piping. (unit in m[ft])
Round up the calculation result to the nearest 0.01kg. (Example: 18.54kg to 18.6kg)
Round up the calculation result in increments of 4oz (0.1kg) or round it up to the nearest 1oz.
(Example: 178.21 to 179oz)
(2) Example:Outdoor unit PUHY-P250YJM-A x 2; Indoor unit PFD-P500VM-E
Outdoor unit model P250
Amount of pre-charged refrigerant in
the outdoor unit (kg)
8.0
Amount of pre-charged refrigerant in
the outdoor unit [lbs-oz]
19-13
Amount of added refrigerant (kg) = (0.29x L
1
) + (0.2 x L
2
) + (0.12 x L
3
) + (0.06 x L
4
) + (0.024 x L
5
) +α
Amount of added refrigerant (oz) = (3.12x L
1
' ) +(2.15 x L
2
' ) + (1.29 x L
3
' ) + (0.65 x L
4
' ) + (0.26 x L
5
' ) + α'
L
1
: Length of ø19.05 [3/4"] liquid pipe (m)
L
2
: Length of ø15.88 [5/8"] liquid pipe (m)
L
3
: Length of ø12.7 [1/2"] liquid pipe (m)
L
4
: Length of ø9.52 [3/8"] liquid pipe (m)
L
5
: Length of ø6.35 [1/4"] liquid pipe (m)
α, α' : Refer to the table below.
L
1
' : Length of ø19.05 [3/4"] liquid pipe [ft]
L
2
' : Length of ø15.88 [5/8"] liquid pipe [ft]
L
3
' : Length of ø12.7 [1/2"] liquid pipe [ft]
L
4
' : Length of ø9.52 [3/8"] liquid pipe [ft]
L
5
' : Length of ø6.35 [1/4"] liquid pipe[ft]
Total capacity of connected indoor units α(kg) α'(oz)
P250 model 2.0 71
P500 model`
*1
*1. For P500 model, the value will be 2.0kg x 2 when two refrigerant circuits are
connected.
4.0 142
CAUTION
Charge liquid refrigerant (as opposed to gaseous refrigerant) into the system.
If gaseous refrigerant is charged into the system, the composition of the refrigerant in the cylinder will change and may
result in performance loss.
Indoor
When the liquid pipe size is 9.52, and the pipe length is 80m,
According to the above formula
Amount of refrigerant to be charged (kg) = 0.06×80+2.0=6.8kg
The final result will be as follows:
Amount of refrigerant to be charged = 6.8kg (for one refrigerant circuit)
9.52[3/8”]
Outdoor
Outdoor
80m[262ft]
80m[262ft]
9.52[3/8”]
According to the above formula
Amount of refrigerant to be charged (oz) = 0.65×262+71 = 241.3oz
The final result will be as follows:
Amount of refrigerant to be charged = 242oz (for one refrigerant circuit)
When the liquid pipe size is [3/8”], and the pipe length is 262ft,