E-17
Answer Memory (Ans) /Previous Answer Memory
(PreAns)
The last calculation result obtained is stored in Ans (answer) memory. The
calculation result obtained prior to the last one is stored in PreAns (previous
answer) memory. Displaying the result of a new calculation will move current
Ans memory contents to PreAns memory and store the new calculation
results in Ans memory. PreAns memory can be used only in the COMP
Mode. PreAns memory contents are cleared whenever the calculator enters
another mode from the COMP Mode.
To divide the result of 3 × 4 by 30 b
3 * 4 =
(Continuing) / 30 =
123 + 456 = 579 B
123 + 456 =
789 – 579 = 210
(Continuing) 789 -G=
For T
k+2
= T
k+1
+ T
k
(Fibonacci sequence), determine the sequence
from T
1
to T
5
. Note however, that T
1
= 1 and T
2
= 1. B
T
1
= 1 1 =
(Ans = T
1
= 1)
T
2
= 1 1 =
(Ans = T
2
= 1, PreAns = T
1
= 1)
T
3
= T
2
+ T
1
= 1 + 1
G+SG(PreAns)=
(Ans = T
3
= 2, PreAns = T
2
= 1)
T
4
= T
3
+ T
2
= 2 + 1 =
(Ans = T
4
= 3, PreAns = T
3
= 2)
T
5
= T
4
+ T
3
= 3 + 2 =
Result: The sequence is {1, 1, 2, 3, 5}.
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