50
Hardware Installation—Installing the
IFC-1010/2020
You may need to test the standby batteries occasionally. Here are
two testing procedures you can use to determine the charge condition and
capacity of the batteries in the system.
Quick Test
The quick test is a measure of charge condition; it is not a battery
capacity test. Use it to identify the need to charge or replace the battery
before it fails. If the battery has been part of an existing system, test results
may indicate a faulty battery or a problem in the charging system.
Follow this procedure:
1. Remove the fully charged battery from the system or charging
network.
2. Place a load resistor across the terminals that limits the current flow to
approximately 1 ampere. For example, use a 12 ohm resistor with a
minimum of 12 watts for a single 12 volt battery. If you have
two 12 volt batteries connected in series, use a 24 ohm resistor with a
minimum of 24 watts.
3. After 15 minutes, measure the voltage across the battery terminals
with the resistor still in place. Be sure to use a digital meter. For a
12 volt battery, the meter reading should range between 13.8 to
2.0 VDC. For a 24 volt battery system, the range is 27.6 to 24 VDC.
Note: If the readings fall below these ranges, perform the 20-hour
discharge test or replace the battery.
20-Hour Discharge Test
The 20-hour discharge test indicates the battery capacity at its ampere
hour rating. The advertised ampere hour battery rating is based on a
20-hour discharge rate, which is the amount of current it delivers to a load
for 20 hours while maintaining its terminal voltage above the levels
described in Step 3 of this test.
Follow this procedure:
1. Calculate the load resistor.
a. Divide the ampere hour rating by 20 hours. For the JC-12250
battery, the calculation would be 25/20=1.25 amperes.
b.
We need 1.25 amperes for 20 hours. Using Ohm’s Law, R=E/I,
therefore, R=12/1.25, or 9.6 ohms. P=I x E, so P=1.25 x 12, or
15 watts. Therefore we need a load resistor of 9.6 ohms at
15 watts.
Battery Testing
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