APPENDICES
APP − 69
A
P
A
L
A
M
=
10000.0( m) 9
=
360448
90000.0
8192(PLS) 44
Here, reduce the above result since the A
P
setting must be made not more than
65535.
A
P
A
L
A
M
=
45056
11250.0
Next, since the A
L
setting range is up to 6553.5, set 1125.0 as A
L
and multiply it by
10 with A
M
.
A
P
L
A
M
=
45056(A
P
)
1125.0(A
L
) 10(A
M
)
Thus, A
P
, A
L
and A
M
to be set are as follows.
A
P
=45056
A
L
=1125.0
A
M
=10
(2) When PULSE (pulse) is set as the control unit
When using PULSE (pulse) as the control unit, set the electronic gear as
follows.
A
P
=number of pulses per motor revolution
A
L
=number of pulses per motor revolution
A
M
=1
For example, when the motor is the HC-MF (8192PLS/rev)
A
P
=8192
A
L
=8192
A
M
=1
(3) When degree is set as the control unit for a rotary axis
When the rotary axis is used, the motor is HC-SF (16384PLS/rev) and the
reduction ratio of the reduction gear is 3/11
Motor
Reduction gear 3/11
First, find how many degrees the load (machine) will travel (∆S) when the motor
turns one revolution (A
P
).
A
P
(number of pulses per motor revolution) =16384 (PLS)
∆S(machine travel value per motor revolution) = 360.00000(degree)×reduction
ratio
=16384(PLS)×3/11
Substitute this for the above relational expression.
At this time, make calculation with the reduction ratio 3/11 remaining as a
fraction.