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Zenith H-100 - Interrupt Mask

Zenith H-100
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3-28
INTERRUPT
MASK
The
interrupt
mask
circuits
ensure
that
interrupt
requests
are
sent
to
the
currently
active
CPU.
The mask
bit.
MSK.
is
set
or
cleared
by
setting
or
clearing
bit
0
of
the
processor
swap
port.
If
set.
and
the
8085
is
active,
the
8085
gets
all
interrupt
requests.
If
cleared.
and
the
8085
is
ac
t i
ve.
the
in
terrupt
request
is
blocked.
However.
the
swap
port
will
disable
the
8085
and
enable
the
8088.
If
the
8088
is
active.
all
interrupt
requests
are
sent
to
the
8088
regardless
of
the
mask
bit.
Here's
hoW
it's
done
.••
Immediately
after
reset.
the
8085
CPU
is
the
active
processor.
Control
lines
5SEL
at
U171-8 and
MSK
at
U112-6
are
logic
one.
These
two
lines
connect
to
U225-9 and
U225-1
O.
shown
near
the
8085
IC
on
the
schematic.
U220-2
inverts
the
resulting
logic
zero
to
enable
U189A
and
U189D.
So
all
interrupts
are
sent
to
the
8085;
maskable
through
U189A.
non-maskable
through
U189D.
The
8SEL
line.
which
is
the
complement
of
5SEL.
disables
U1898
and
U189C.
the
AND
gates
to
the
8088.
Later.
when
the
8085
hands
control
to
the
8088
CPU.
8SEL
will
go
high
and
5SEL
will
go low.
If.
while
the
8085
is
selected.
the
MSK
line
is
set
to
logic
zero.
U220-2
disables
U189A
and
U189D.
This
blocks
the
interrupt
request
from
both
the
8085 and
the
8088.
However.
if
an
interrupt
request
should
occur.
either
standard
or
NMI,
U156-6
will
go
high
to
assert
the
NMINT
line.
The
NMINT
line
connects
to
U155-9
in
the
processor
swap
port.
The
other
input
is
the
MSK
line
which
is
also
high.
As
a
result,
U155-8
goes
low
to
assert
the
8SEL
line.
The
H/Z-100 swaps
to
the
8088
processor
as
described
previously.
When
the
8088
CPU
is
active.
8SEL
is
high
to
enable
U1898
and
U189C. U189A
and
U189D
are
disabled
because
5SEL
is
logic
zero
at
U225-9.
So,
no
matter
what
the
setting
of
the
R:rK
bit
at
U?25-10.
all
interrupt
requests
will
be
routed
to
the
BOB8
processor.

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