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Electro-Voice 7600 - Adjusting R23 and R24, the Negative and Positive Current Limit Trimpots

Electro-Voice 7600
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Operating
and
Servicing
Instructions
for
the
Electro-Voice
7600
Power
Amplifier
the
unit
is
in
the
Dual
mode
with
8
Cl
loads
con¬
nected
to
each
channel.
2.
Remove
the
eleven
screws
securing
the
top
cover.
Refer
to
Figure
1
for
the
screw
locations.
3.
Connect
the
sinewave
generator
output
of
the
analyzer
to
the
input
of
Channel
1.
Rotate
the
in¬
put
level
control
of
Chan¬
nel
1
to
its
full
clockwise
position.
Rotate
the
input
level
control
of
Channel
2
to
its
full
counter-clock¬
wise
position.
4.
Apply
power
to
the
amp¬
lifier
and
adjust
the
sinewave
generator
for
a
1
kHz,
0
dBu
(0.775
V
rms)
output
level.
For
this
ad¬
justment,
it
is
not
nec¬
essary
to
maintain
a
con¬
stant
120
V
ac
line
input
voltage
under
load.
5.
Find
R26
on
the
compon¬
ent
layout
in
Figure
12.
Rotate
the
shaft
of
R26
slowly
clockwise
until
the
spikes
are
minimized
in
the
distortion
waveform
as
shown
in
Figure
9.
6.
Repeat
steps
3
through
5
for
Channel
2.
7.
Check
the
ac
idle
current
draw.
With
both
channels
at
idle,
the
ac
line
current
should
be
approximately
1
amp
or
less.
If
the
idle
current
draw
exceeds
1
amp,
rotate
R26
counter¬
clockwise
slightly
on
both
channels
until
the
idle
current
is
no
more
than
1
amp.
8.
Turn
off
the
generator’s
output
signal.
If
you
have
concluded
with
the
test
and
alignment
procedures,
disconnect
the
amplifier
from
its
power
source
and
re-install
the
top
cover
with
the
eleven
screws
previously
removed.
9.5
Adjusting
R23
and
R24,
the
Negative
and
Posi¬
tive
Current
Limit
Trimpots
Shown
in
Figure
11
is
an
asymmetrically
clipped
waveform
caused
by
an
improperly
adjusted
positive
current
limit
as
deter¬
mined
by
R24.
Had
R23
been
imp¬
roperly
adjusted,
the
negative
half
of
the
waveform
would
be
clipped
as
well,
but
its
degree
of
clipping
is
a
function
of
R23
only
and
is
independent
of
R24.
In
the
following
procedures,
you
will
be
adjusting
the
current
limit
thresholds
by
varying
R23
and
R24
in
such
a
way
so
as
to
insure
symmetrical
clipping.
1.
Turn
power
off
and
dis¬
connect
unit
from
power
source.
Make
sure
the
unit
is
in
the
Dual
mode
with
a
2
fl
load
connected
to
the
channel
under
test.
If
you
do
not
have
a
2
fl
load,
you
may
use
a
4
fl
load
or
even
an
8
fl
load.
The
higher
the
load
impe¬
dance,
however,
the
less
likely
it
is
you
will
have
symmetrical
clipping
on
peaks
into
lower
impe¬
dance
loads.
2.
Remove
the
eleven
screws
securing
the
top
cover.
Refer
to
Figure
1
for
the
screw
locations.
3.
Connect
the
sinewave
gen¬
erator
output
of
the
anal¬
yzer
to
the
input
of
Chan¬
nel
1.
Rotate
the
input
level
control
of
Channel
1
to
its
full
clockwise
posi¬
tion.
Rotate
the
input
le¬
vel
control
of
Channel
2
to
its
full
counter-clock¬
wise
position.
4.
Find
R23
and
R24
on
the
component
layout
in
Fig¬
ure
12.
Reach
into
the
amplifier
and
rotate
the
shafts
of
R23
and
R24
to
their
full
clockwise
posi¬
tions.
5.
Apply
power
to
the
ampli¬
fier
and
adjust
the
sine¬
wave
generator
for
a
1
kHz,
—10
dBu
(0.245
V
rms)
output
level.
For
this
adjustment,
it
is
not
nec¬
essary
to
maintain
a
con¬
stant
120
V
ac
line
input
under
load.
6.
Increase
the
level
of
the
generator
until
the
output
of
the
amplifier
reaches
42.43
V
rms
(which
corre¬
sponds
to
900
watts
out¬
put
into
the
2
Cl
load).
The
ac
line
current
draw
will
be
approximately
19
amps.
Although
the
fuse
installed
is
a
15
amp
fuse,
it
should
not
blow
during
this
test
unless
the
amp¬
lifier
is
operated
contin¬
uously
for
an
extended
period
of
time.
If
a
2
fl
load
is
unavail¬
able,
use
either
the
4
or
8
fl
load
and
increase
the
generator
output
level
ac¬
cordingly
to
the
corres¬
ponding
rated
output
po¬
wer.
7.
While
monitoring
the
dis¬
tortion
waveform
on
the
oscilloscope,
rotate
R23
counter-clockwise
until
the
negative
half
of
the
waveform
just
begins
to
visibly
clip
(more
pro¬
nounced
spikes
will
ap-
14
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a
Mark
TV
Company

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